y=3x^2-3/4x

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Solution for y=3x^2-3/4x equation:


x in (-oo:+oo)

y = 3*x^2-((3/4)*x) // - 3*x^2-((3/4)*x)

(3/4)*x-(3*x^2)+y = 0

(3/4)*x-3*x^2+y = 0

3/4*x-3*x^2+y = 0

DELTA = (3/4)^2-(-3*4*y)

DELTA = 12*y+9/16

12*y+9/16 = 0

12*y+9/16 = 0 // - 9/16

12*y = -9/16 // : 12

y = -9/16/12

y = -3/64

DELTA = 0 <=> t_1 = -3/64

x = -3/4/(-3*2) i y = -3/64

x = 1/8 i y = -3/64

( x = ((12*y+9/16)^(1/2)-3/4)/(-3*2) or x = (-(12*y+9/16)^(1/2)-3/4)/(-3*2) ) i y > -3/64

( x = ((12*y+9/16)^(1/2)-3/4)/(-6) or x = ((12*y+9/16)^(1/2)+3/4)/6 ) i y > -3/64

y+3/64 > 0

y+3/64 > 0 // - 3/64

y > -3/64

x in { 1/8, ((12*y+9/16)^(1/2)-3/4)/(-6), ((12*y+9/16)^(1/2)+3/4)/6 }

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